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《山东大学学报(理学版)》 ›› 2026, Vol. 61 ›› Issue (8): 132-144.doi: 10.6040/j.issn.1671-9352.0.2025.159

• • 上一篇    

智能化背景下新能源汽车供应链合作模式

朱梦萍1,罗立娇1,王启飞2*   

  1. 1.武汉科技大学管理学院, 湖北 武汉 430065;2.华中科技大学公共管理学院, 湖北 武汉 430074
  • 发布日期:2026-08-12
  • 通讯作者: 王启飞(1990— ),男,副教授,博士,研究方向为可持续发展政策. E-mail:qifeiwang@hust.edu.cn
  • 作者简介:朱梦萍(1991— ),女,讲师,博士,研究方向为物流与供应链管理. E-mail:zhumengping@wust.edu.cn*通信作者:王启飞(1990— ),男,副教授,博士,研究方向为可持续发展政策. E-mail:qifeiwang@hust.edu.cn
  • 基金资助:
    国家自然科学基金资助项目(72201196,71901099)

Supply chain cooperation modes for new energy vehicles under the background of intelligentization

ZHU Mengping1, LUO Lijiao1, WANG Qifei2*   

  1. 1. School of Management, Wuhan University of Science and Technology, Wuhan 430065, Hubei, China;
    2. College of Public Administration, Huazhong University of Science and Technology, Wuhan 430074, Hubei, China
  • Published:2026-08-12

摘要: 本文构建了包含智能系统供应商和新能源汽车制造商的二级供应链模型。针对制造商主导和供应商主导的合作模式,本文利用Stackelberg博弈方法得到了供应链成员的均衡决策和利润,进一步分析了新能源汽车供应链的合作模式选择问题。研究发现:(1)当销售收入分配比例和研发成本系数都超过一定阈值时,智能系统供应商主导模式下产品的智能化水平更高;(2)智能化研发成本系数和弹性系数对于均衡决策具有重要影响;(3)对于制造商和供应商而言,两种合作模式的选择受到销售收入分配比例的影响。在供应商模式下,通过设置合理的销售收入分配比例,可以使得制造商和供应商都获得更高的利润,即实现双赢结果。

关键词: 智能化, 新能源汽车, 供应链, 合作模式, 销售收入分配

Abstract: This paper constructs a two-tier supply chain model involving an intelligent system supplier and a new energy vehicle(NEV)manufacturer. Focusing on cooperation modes led by the manufacturer and the supplier, this study employs the Stackelberg game approach to derive the equilibrium strategies and profits of supply chain members, and further examines the selection of cooperation modes in the NEV supply chain. The findings reveal that:(1)When the sales revenue allocation ratio and the R& D cost coefficient exceed a certain threshold, the supplier-led mode results in a higher level of product intelligentization;(2)The R& D cost coefficient and elasticity coefficient exert a significant impact on equilibrium decisions;(3)For both the manufacturer and the supplier, the choice between cooperation modes is influenced by the sales revenue allocation ratio. Under the supplier-led mode, by setting a reasonable sales revenue allocation ratio, both the manufacturer and the supplier can achieve higher profits, thereby realizing a win-win outcome.

Key words: intelligentization, new energy vehicle, supply chain, cooperation mode, sales revenue allocation

中图分类号: 

  • F272
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[40] 东方财富网. 赛力斯: 2024年年度报告[EB/OL].(2025-04-01)[2025-04-20]. https://data.eastmoney.com/notices/detail/601127/AN202503311649710345.html. Eastmoney.com. SERES: 2024 Annual Report[EB/OL].(2025-04-01)[2025-04-20]. https://data.eastmoney.com/notices/detail/601127/AN202503311649710345.html. 附录 命题1的证明 根据逆向归纳法,首先求式(2)关于p的二阶导(ə2πMm(p,I))/(əp2)=-2 β<0,则πMm(p,I)是关于p的凹函数。由一阶条件(əπMm)/(əp)=0,可得p=(α+(c+w)β+γI)/(2 β)。将p=(α+(c+w)β+γI)/(2 β)代入式(1)中,求出式(1)关于w的二阶导(d 2πMs(w))/(dw2)=-β<0,则πMs(w)是关于w的凹函数,由一阶条件(dπMs(w))/(dw)=0,可得w=(2α-2c β+k βI 2+2γI)/(4 β)。将w=(2α-2c β+k βI 2+2γI)/(4 β)代入p=(α+(c+w)β+γI)/(2 β)中,得到p=(6α+2c β+k βI 2+6γI)/(8β)。将w=(2α-2c β+k βI 2+2γI)/(4 β)和p=(α+(c+w)β+γI)/(2 β)代入式(2),得到πMm(I)=([2α-2c β+2γI-k βI 2] 2)/(64 β)。 在实践中制造商的边际利润为正,需要保证p-w-c=(2α-2c β+2γΙ-k βΙ2)/(8β)>0,即2α-2c β+2γΙ-k βΙ2>0。因此,最大化πMm(I)即等价于最大化2α-2c β+2γI-k βI 2。定义f(I)=2α-2c β+2γI-k βI 2,可得(df(I))/(dI)=2γ-2k βI且(d2f(I))/(dI 2)=-2k β<0。可知f(I)为关于I的凹函数,根据上述一阶条件,可得I M*=γ/(k β)。 将I M*=γ/(k β)代入w=(2α-2c β+k βI 2+2γI)/(4 β)和p=(6α+2c β+k βI 2+6γI)/(8β)中,可得wM*=(2k β(α-c β)+3γ2)/(4k β 2), pM*=1/8(2c+(6kα β+7γ2)/(k β 2))。 将I M*、wM*、 pM*代入式(1)、(2),可得πM*s=([2k β(α-c β)+γ2] 2)/(32k2 β3), πM*m=([2k β(α-c β)+γ2] 2)/(64k2 β3)。 命题2的证明 根据逆向归纳法,首先求式(4)关于p的二阶导(d2πSm(p))/(dp2)=-2 β(1-σ)<0,可知πSm(p)是关于p的凹函数。由一阶条件(dπSm(p))/(dp)=0,可得p=1/2((α+γI)/β+c/(1-σ))。将p=1/2((α+γI)/β+c/(1-σ))代入式(3)中,得到利润 πSs(I)=([c β+α(-1+σ)+γΙ(-1+σ)] {k βΙ2-[α+c β+Ι(γ+k βΙ)] σ+(α+γΙ)σ2})/(4 β(-1+σ)2)。(A1) 式(A1)是关于I的三次函数,基于一阶条件(dπSs(I))/(dI)=0,可得2个驻点I1=(Z+β A)/(3k βγ(1-σ))或I2=(Z-β A)/(3k βγ(1-σ))。对于这2个驻点来说,只有当二阶导数小于0,利润函数取得最大值;否则,利润函数取得最小值。 式(3)关于I的二阶导(d2πSs(I))/(dI 2)=1/2[(γ2σ)/β-k(α+3γI)+(ck β)/(1-σ)] ,将I1、I2分别代入以上表达式,可得I1对应的二阶导数为 -((k2[c β+α(-1+σ)] 2-(2k γ2[c β-2α(-1+σ)] (-1+σ)σ)/β+(γ4(-1+σ)2σ2)/(β 2))1/2)/(2(1-σ))<0, 对应πSs(I)的最大值;I2对应的二阶导数为 ((k2[c β+α(-1+σ)] 2-(2k γ2[c β-2α(-1+σ)] (-1+σ)σ)/β+(γ4(-1+σ)2σ2)/(β 2))1/2)/(2(1-σ))>0, 对应πSs(I)的最小值。因此I S*=I1=(Z+β A)/(3k βγ(1-σ))。 将I S*=(Z+β A)/(3k βγ(1-σ))代入p=1/2((α+γI)/β+c/(1-σ)),可得 pS*=(γ2(1-σ)σ+2k β(α+2c β-ασ)+β A)/(6k β 2(1-σ))=(Y+β A)/(6k β 2(1-σ))。 将IS*、 pS*代入式(3)和式(4),可得供应链各成员的利润分别为 πS*s=(3σ(X+β A)(Y+β A))/(108k2 β3(1-σ)2)-((X+β A)(Z+β A)2)/(108k2 β3(1-σ)3γ2), πS*m=({A β+2k β[-c β+α(1-σ)] +γ2(1-σ)σ}2)/(36k2 β3(1-σ))=((A β+X)2)/(36k2 β3(1-σ))。 注 A=(k2[α(1-σ)-c β] 2+(γ4(1-σ)2σ2)/(β 2)+(2k γ2(1-σ)σ(2α+c β-2ασ))/β)1/2, X=2k β[α(1-σ)-c β] +γ2(1-σ)σ,Y=γ2(1-σ)σ+2k β(α+2c β-ασ), Z=k β[α(1-σ)-c β] +γ2(1-σ)σ。 定理1的证明 ΔI=I M*-I S*=(A β+k β[c β-α(1-σ)] - γ2(3-σ)(1-σ))/(3k βγ(σ-1)),由于(ə(ΔI))/(əA)=1/(3k γ(σ-1))<0,所以ΔI关于A单调递减,关于A的临界值为:(~overA)1=(γ2(3-σ)(1-σ)+k β(α-c β-ασ))/β。 因此,当A>(~overA)1=(γ2(3-σ)(1-σ)+k β(α-c β-ασ))/β时,I M*S*;反之I M*≥I S*。注意到,A>(~overA)1可以等价于A2>(~overA)21, A2-(~overA)21=(3γ2(-1+σ){2k β[α(1-σ)2-c β] +γ2(1-σ)(3-2σ)})/(β 2)。 (1)在供应商模式下,供应商有较大的渠道权力确保其销售收入分配不低于一定比例。因此,α(1-σ)2-c β<0是一个合理的设定。在此情形下,A2-(~overA)21关于k单调递增,且临界条件为(~overk)=(γ2(1-σ)(3-2σ))/(2 β[c β-α(1-σ)2] )。当k>(~overk)时,有A2-(~overA)21>0,此时 I M*S*;否则,I M*≥I S*。 (2)当α(1-σ)2-c β>0时,I M*>I S*恒成立。 综合以上两种情况且进一步化简,可以得到当σ>1-((c β)/α)1/2且k>(γ2(1-σ)(3-2σ))/(2 β[c β-α(1-σ)2] )时,I M*S*;否则,I M*≥I S*。 定理2的证明 Δp=pM*-pS*=(4A β-γ2(1-σ)(21-4σ)+2k β[5α(-1+σ)+c β(5+3σ)] )/(24k β 2(-1+σ)),(ə(Δp))/(əA)=1/(6k β(σ-1))<0,因此Δp关于A单调递减,关于A的临界值为(~overA)2=(γ2(1-σ)(21-4σ)-2k β[c β(5+3σ)-5α(1-σ)] )/(4 β)。 因此,当A>(~overA)2=(γ2(1-σ)(21-4σ)-2k β[c β(5+3σ)-5α(1-σ)] )/(4 β)时,pM*S*;反之,pM*≥pS*。 定理3的证明 ΔD=DM*-DS*=(4A β+γ2[(7-4σ)σ-3] -2k β[c β(1+3σ)-α(1-σ)] )/(24k β(-1+σ)),(ə(ΔD))/(əA)=1/(6k(σ-1))<0,因此ΔD关于A单调递减,关于A的临界值为(~overA)3=(γ2(1-σ)(3-4σ)+2k β[c β(1+3σ)-α(1-σ)] )/(4 β)。当A>(~overA)3=(γ2(1-σ)(3-4σ)+2k β[c β(1+3σ)-α(1-σ)] )/(4 β)时,DM*S*;反之,DM*≥DS*。 定理4的证明 ΔπmM*mS*m=([2k β(α-c β)+γ2] 2)/(64k2 β3)-((A β+X)2)/(36k2 β3(1-σ)),(ə(Δπm))/(əA)=(X+A β)/(18k2 β 2(σ-1))<0,因此,Δπm关于A单调递减,关于A的临界值为(~overA)4=(3[2k β(α-c β)+γ2] (1-σ)1/2)/(4 β)- X/β。 因此,当A>(~overA)4=(3[2k β(α-c β)+γ2] (1-σ)1/2)/(4 β)- X/β时,πM*mS*m;反之,πM*m≥πS*m
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